Posted by Qurr on 13 May 2012 /
1 Comment
A friend asked me to solve this Mathematical Card Trick called “The Final 3″, to show why it works.
The Final 3 – Amazing Math Card Trick by mismag822
And here’s my solution
The trick begins with 52 cards, and the spectator takes 3 of them, let’s say X, Y, and Z.
Out of the other 49 cards; 40 are dealt FACE-DOWN into piles of 10, 15, 15;
leaving a remnant of 9 cards
- Pile 1 has 10 cards, Pile 2 has 15 cards, Pile 3 has 15 cards
- Spectator puts card X on Pile 1, making 11 cards on Pile 1.
- This means card X is in position 1 counting from Pile 1′s top
- Spectator cuts Pile 2 anywhere and places on Pile 1.
- Let’s say she cuts it at Q cards from the top of Pile 2.
- Thus, Pile 1 is now 11+Q cards and card X is number Q+1 from the top of Pile 1.
- Pile 2 now has 15-Q cards
- Spectator places card Y on Pile 2, making 15-Q+1 cards on Pile 2.
- Thus card Y is at position 1 from the top of Pile 2
- Spectator cuts Pile 3 anywhere and places on Pile 2.
- Let’s say she cuts it at R cards from the top of Pile 3.
- Thus, Pile 2 is now 15-Q+1+R cards and card Y is now at position R+1 cards from the top of Pile 2
- Pile 3 now has 15-R cards
- Spectator places card Z on Pile 3, making 15-R+1 cards on Pile 3.
- Thus card Z is at position 1 from the top of Pile 3.
- Spectator places the 9 remaining cards on pile 3.
- Thus card Z is at position 9+1 = 10 from top of pile 3
- And pile 3 now has (15-R+1)+9 = 25-R cards
- Dealer places pile 3 on pile 2, let’s call this Pile3+2
- Naturally, pile3+2 will have (pile2)+(pile3) cards, i.e. (15-Q+1+R)+(25-R) cards = 41-Q cards
- This pile3+2 will contain cards Y (from pile 2) and Z (from pile 3).
- Card Z position is still the 10th card from the top since pile 3 is on top of pile 3+2
- Card Y position is now shifted down by (25-R) cards (the height of pile 3, since pile 3 is upon pile 2) i.e. (R+1)+(25-R) = 26
- Dealer places Pile3+2 upon Pile 1, lets call this Pile3+2+1
- Once again, Pile3+2+1 will have (pile3+2)+(pile1) cards i.e. (41-Q)+(11+Q) = 52 cards in all
- This Pile3+2+1 will have all three cards X,Y, Z from initial 3 piles
- Card Z and Y positions from the top will not change, since the Pile3+2 is on top of pile 1
- This means Card Z is still at number 10 and card Y is still number 26
- Pile 1 has been shifted down by (41-Q) cards which was the height of Pile3+2
- Thus Card X is now in position (Q+1)+(41-Q) i.e. 42
- Dealer cuts 4 cards from the top of pile, to the bottom; this shifts card positions by 4
- Card Z, Y and X are now in positions 10 minus 4, 26 minus 4 and 42 minus 4 i.e. 6,22,38
- Now for the fun part. Dealer deals cards into 2 groups, face up & face down
- The dealer deals face up, first
- Since there are two piles, there will be an odd pile (face up) and an even pile (face down)
- The dealer is seeking cards 6,22 and 38 so he must keep the face down pile
- The face up cards are 1,3,5,7…51 and face down cards are 2,4,6,…52
- THIS process has also reversed the direction of the numbering of the cards (first-in becomes last-out, like putting some stuff in a container, when you fetch it out the order is reversed)
- Dealer repeats face-up and face-down alternate deals
- The dealer deals face up, first. Once again, an odd pile and an even pile
- The odd pile is the set of numbers 2M where M is odd e.g. 2,6,10,14,…50
- The even pile is the set of numbers 2N where N is even e.g. 4,8,12,16,…52
- Because of the reversal in (11e) above, odd pile is now face-down pile.
- The even pile is discarded
- Note that there is a second reversal due to the LIFO (Last In First Out)
- Dealer does the face-up and face-down alternate deals again
- The dealer deals face up, first. Again, an odd pile and an even pile
- Due to the LIFO in (xi)(f), odd pile is now face-up pile, to be discarded
- The odd pile has 2,10,18,26,34,42,50 and the even has 6,14,22,30,38,46
- Keep the face-down even pile and discard the face-up (odd) pile
- Another LIFO reversal
- Finally the dealer alternates deals for the last time
- The dealer deals face up, first; into 2 piles. Evens will be face-up now
- Since he is dealing 6,14,22,30,38,46 into two piles; odds will be 6,22,38 and evens are 14,30,46
- The dealer discards the 14,30,46 (even pile, face-up)
- Dealer presents 6,22 and 38 as the chosen cards
- But we already knew the chosen cards. We’ve been tracking them all along.
- Important point here was to tell the spectator “Say stop when you see your card”
- This distracts the spectactor in case she is sneaky and wants to be counting/tracking the cards
- The spectator’s cards will NEVER come up; never any chance to say “stop”.
That’s all Folks!











1 Comment
I got stuck at No 12.Bullet no 2
Why the double progression at that point? 2 by the odds and 2 by evens